by **sadmin** » Mon Aug 28, 2017 2:02 am

QCS-6

Average - Practice Questions

Q30

Average salary of officers, clerks, and bearers:1200, 450 and 180 respectively.

Average salary of the three classes = Rs 440

Raise in salary in the new scale of pay - officers, clerks, and bearers- 60, 30 and 20 Rs respectively

New monthly average salary= Rs 470

In the initial pay scale:

Initially,

total salary = salary of all officers + salary of all clerks + salary of all bearers

Assume the the number of officers, clerks and bearers to be a,c, and b

thus we have=> 440 (a+b+c) =1200(a) + 450(b) +180(c)

On simplifying the above equation we have : 440a + 440b + 440c = 1200a + 450c + 180b

=> 760a +260 c = 10b => 76 a + 10c = 260b => 76a + c = 26 b................(i)

Similarly, after the new payscale is launched -we can write a similar equation:

total salary = salary of all officers + salary of all clerks + salary of all bearers

Thus we have : 470 (a +b +c) = 1260 a + 480 c + 200 b

=> 790a + 10 c = 270 b => 79a + c = 27 b .............(ii)

From i and ii we have

76a + c = 26 b

79a + c = 27 b .

For such questions , we need to get a and c in terms of b. That is the number of officers and clerks in terms of the number of bearers.

Subtracting i from ii we get:

3a = b or the number of officers = a =b/3 ..........iii

Putting the value of iii in i we get

76 . (b/3) + c = 26b => c =2b/3

Thus the total number of employees = number of officers + number of clerks + number of bearers = b/3+ 2b/3+ b

=> Total employees = 2b

Number of officers = b/3

Percentage of officers = (Number of officers / total of employees ) x 100 = (b/3) /(2b) x 100 = 16.66 % or

Ans option (b)