 ## QCS-8- Profit and Loss

In this forum, please discuss the questions appearing in the QA class sheets :especially the practice and the DS questions at the end of the sheet.

### QCS-8- Profit and Loss

QCS-8 Q19

Intial SP = Rs 5000

Assume CP = X

lOSS = X - 5000

If the sp increases to 5600, there is a profit whose numerical amount is double the former loss
Profit = 5600 -X

Profit = 2 LOSS = > 5600-X = 2( X-5000)
On solving the above equation we get X = 5200

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Joined: Wed Feb 13, 2013 5:51 am

### Re: QCS-8- Profit and Loss

QCS-8 Q Number 25

Assume CP = X Rs
Marked price = x + 40% of x = 1.4x
SP = Marked price - Discount = 1.4x - 10% of (1.4x) = 1.26 x

Profit = Rs 65 = SP -CP

65 = 1.26X -X
OR X = 65/0.26 OR X = 250

Posts: 228
Joined: Wed Feb 13, 2013 5:51 am

### Re: QCS-8- Profit and Loss

QCS-8- Q NO.26

For such questions always assume the values of cost price and the number of units in the consignment in such a way that the total cost comest to Rs 100. ( It simplifies our calculation)

assume CP = Re 1 AND Number of units in teh consignment = 100 units
Total Cost= Rs 100

Marked Price = CP + 50% OF CP = 1 + 50% OF 1= 1.5 Rs

Similarly, there are two SPs given one of which is the CP itself and the ohter one is discounted by 4 %

SP1 = 1.5 - 4% OF 1.5 = 1.44 Rs

Now when the merchant Sells his good - he sells one third at the marked price, onethird of the remainder at 1.44 Rs ( 4% discount) and the rest at CP

His net realization would be as follows

100/3 units @ 1.5 Rs = 50 Rs thus the balance units = 100-100/3 = 200/3 UNITS
1/3rd of 200/3 = 200/9 units he sold at 1.44 Rs
200/9 *1.44 = Rs 32 AND NOW, The balance units = 200/3 - 200/9 = 400/9 units
The remaining units he sold at 1 re . His realization on them would be
200/9 *1 = 44.44

Total realization = 50 + 32 + 44.44 = 126.44

Thus the profit % = (126.44 -100)/100 *100 = 26.44%

Posts: 228
Joined: Wed Feb 13, 2013 5:51 am

### Re: QCS-8- Profit and Loss

QCS-8 Q NO-27

Assume the CP of one of the clocks = x
Therefore, the CP of teh other clock = x +25% of x = x + 1/4x = 5/4x

Now he sells the dearer one at a profit of 10% and the cheaper one at a profit of 7.5%. The basic equation would be

SP of dearer + SP of the cheaper = 98 ( Note : Rs 98 is not mentioned as the profit in this question)

(5/4x + 10% of 5/4x) + ( x + 7.5% of x ) = 98
On solving the above equation you should get the value of x = 40 Rs which is the COST price of the cheaper clock
AND Rs 50 AS THE cost price of the dearer clock

Posts: 228
Joined: Wed Feb 13, 2013 5:51 am

### Re: QCS-8- Profit and Loss

QCS-8 QNO- 28

Assume that the cost PRICE Of the bikes = Rs x
The man bought 40 bikes and sold 3/4th of them that is 30 of them on cash and the rest, that is 10 of them for credit

Marked Price = 1.25 x

Selling PRICE for cash sale = 1.25x - 10% of 1.25x = 0.9(1.25x)
Selling Price for Credit sale = 1.25x - 5% of 1.25x = 0.95(1.25x)

Total Sale - Total Cost= Profit
0.9(1.25x)(30) + 0.95(1.25x)(10) - 40x = 2025
On solving the above equation you get the value of X = 360 Rs 